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12m^2-13=-6m
We move all terms to the left:
12m^2-13-(-6m)=0
We get rid of parentheses
12m^2+6m-13=0
a = 12; b = 6; c = -13;
Δ = b2-4ac
Δ = 62-4·12·(-13)
Δ = 660
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{660}=\sqrt{4*165}=\sqrt{4}*\sqrt{165}=2\sqrt{165}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{165}}{2*12}=\frac{-6-2\sqrt{165}}{24} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{165}}{2*12}=\frac{-6+2\sqrt{165}}{24} $
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